10. How Much Electric You Need to Waste for Heating the Water
1) For 58x1800mm, the needed heat to increase 1oC by vacuum tubeQ=CMT=4.2x103J/KGoCx142KGx1oC=596.4x103J=0.6MJ
2) To increase 10oC, if increase to 45oC, totally need:
Q=0.6MJx (45oC-10oC) =21MJ
3.If heating by electric:
21x106J=1500W x T(s)
T=1.4x104s=3.9h